How do you solve $\sqrt{x - 2} = 4$ $sqrt(x-2)=4$ ?

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How do you solve $\sqrt{x - 2} = 4$ $sqrt(x-2)=4$ ?

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Answer 1 · 2018-06-04T09:26:15

$x = 18$ $x=18$

Explanation:

$square both sides$ $color(blue)"square both sides"$

${(\sqrt{x - 2})}^{2} = 4^{2}$ $(sqrt(x-2))^2=4^2$

$x - 2 = 16$ $x-2=16$

$add 2 to both sides$ $"add 2 to both sides"$

$x = 16 + 2 = 18$ $x=16+2=18$

$As a check$ $color(blue)"As a check"$

$\sqrt{18 - 2} = \sqrt{16} = 4 = right side$ $sqrt(18-2)=sqrt16=4=" right side"$

$x = 18 is the solution$ $x=18" is the solution"$

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How do you solve $\sqrt{x - 2} = 4$ $sqrt(x-2)=4$ ?

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How do you solve $\sqrt{x - 2} = 4$ $sqrt(x-2)=4$ ?