How do you solve #sqrt(x+2) = x-4#?
1 Answer
May 10, 2016
Explanation:
First square both sides of the equation, noting that this may introduce spurious solutions:
#x+2 = (x-4)^2 = x^2-8x+16#
Subtract
#0 = x^2-9x+14 = (x-2)(x-7)#
So
If
If
So