How do you solve sqrt(x-4) - 4=6? Algebra Radicals and Geometry Connections Radical Equations 2 Answers Veddesh phi Jan 26, 2016 x=104 Explanation: sqrt(x-4)-4=6 rarrsqrt(x-4)=6+4=10 Square both sides rarr(sqrt(x-4))^2=10^2 rarrx-4=100 rarrx=100+4=104 Answer link Jim G. ยท Veddesh phi Jan 26, 2016 x = 104 Explanation: Add 4 to both sides Hence sqrt(x - 4) = 10 Square both sides: rarr (sqrt(x - 4 ))^2 = 10^2 So x - 4 = 100 rArr x = 104 Answer link Related questions How do you solve radical equations? What are Radical Equations? How do you solve radical equations with cube roots? How do you find extraneous solutions when solving radical equations? How do you solve \sqrt{x+15}=\sqrt{3x-3}? How do you solve and find the extraneous solutions for 2\sqrt{4-3x}+3=0? How do you solve \sqrt{x^2-5x}-6=0? How do you solve \sqrt{x}=x-6? How do you solve for x in ""^3sqrt(-2-5x)+3=0? How do you solve for x in sqrt(42-x)+x =13? See all questions in Radical Equations Impact of this question 1749 views around the world You can reuse this answer Creative Commons License