How do you solve #sqrt(x+6)-2=sqrt(x-2)#?

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Answer 1 · 2016-04-29T19:41:05

#x=3#

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Square both sides

#(sqrt(x+6)-2)^2=x-2#

#(cancel(x)+6) -4sqrt(x+6)+4=cancel(x)-2#

#10-4sqrt(x+6)=-2#

#4sqrt(x+6)=12#

#sqrt(x+6)=3#

square both sides

#x+6=9#

#x=3#