How do you solve #sqrt(x+7)+2=4#?

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Answer 1 · 2015-10-12T20:35:19

#x=-3#

Re-arranging the equation we get

#sqrt(x+7)=2#

Now squaring both sides we get

#+-(x+7)=4#

#therefore x=-11 or x=-3#

Clearly #x!=-11# since this results in a value #!in RR#

#therefore x=-3#