How do you solve #sqrt(x+8)=5#?

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Answer 1 · 2017-09-10T01:33:11

#x=17#

Square both sides to cancel out the square root

#sqrt(x+8)^2=5^2#

#x+8=25#

Subtract #8# from both sides to solve for #x#

#x+8color(red)(-8)=25color(red)(-8)#

#x+0=17#

#x=17#