Question

How do you solve `sqrt7^(6x)= 49^(x-6)`?

Answer 1

`x = -12`

Explanation:

Replace `sqrt7` by `7^(1/2)` and 49 by `7^2.`.

Now, use `(a^m)^n=a^(mn)`.

`7^(3x)=7^(2x-12)`, Compare exponents..

`3x=2x-12`.

`x=-12`.