How do you solve the equation and identify any extraneous solutions for #a=sqrt(-2a)#?
1 Answer
Jun 27, 2015
First square both sides (which may add extraneous solutions) to get:
One solution of this is
Explanation:
If we square both sides of the original equation then we get:
This must hold in order that
This new equation has two solutions:
When
So
When
So