How do you solve the equation $log_3 5+log_3 x=log_3 10$ ?

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Answer 1 · 2016-11-20T15:12:34

$log_3 5 + log_3 x = log_3 10$

$log_3 x= log_3 10 - log_3 5$

Use the subtraction rule of logarithms: $log_a n - log_a m = log_a(n/m)$ .

$log_3 x = log_ 3 (10/5)$

$log_3 x = log_3 2$

If $loga = logb$ , then $a = b$ .

$x = 2$

Hopefully this helps!

How do you solve the equation log_3 5+log_3 x=log_3 10log_3 5+log_3 x=log_3 10?