How do you solve the equation #sqrt(10c)+2=5#?

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Answer 1 · 2017-04-29T20:36:34

See the solution process below:

First, subtract #color(red)(2)# from each side of the equation to isolate the square root term while keeping the equation balanced:

#sqrt(10c) + 2 - color(red)(2) = 5 - color(red)(2)#

#sqrt(10c) + 0 = 3#

#sqrt(10c) = 3#

Next, square each side of the function to eliminate the square root while keeping the equation balanced:

#(sqrt(10c))^2 = 3^2#

#10c = 9#

Now, divide each side of the equation by #color(red)(10)# to solve for #x# while keeping the equation balanced:

#(10c)/color(red)(10) = 9/color(red)(10)#

#(color(red)(cancel(color(black)(10)))c)/cancel(color(red)(10)) = 9/10#

#c = 9/10#