How do you solve the equation #x^2-16x=-20# by completing the square?

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Answer 1 · 2017-06-04T15:28:48

#x=8+-2sqrt11#

#x^2-16x=-20#

#x^2-16x+8^2-8^2=-20#

#(x-8)^2-64=-20#

#(x-8)^2=44#

#x-8=+-sqrt44=+-2sqrt11#

#x=8+-2sqrt11#