How do you solve the following system of equations?: $-3x+y=6, 3x + 19y=19$ ?

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Answer 1 · 2015-12-26T19:57:50

The solution is shown below using substitution method.

-3x + y = 6
y = 6 + 3x
3x + 19(6 + 3x) = 19
3x + 114 + 57x = 19
60x = -95
x = $-19/12$
-3( $-19/12$ ) + y = 6
$19/4$ + y = 6
y = 6 - $19/4$
y = $5/4$

The solution set would be ( $-19/12$ , $5/4$ )

How do you solve the following system of equations?: -3x+y=6, 3x + 19y=19-3x+y=6, 3x + 19y=19?