How do you solve the following system of equations?: #-x- 16y = 12 , 12x+y=8#? Algebra Systems of Equations and Inequalities Linear Systems with Addition or Subtraction 1 Answer sankarankalyanam Jun 20, 2018 #color(gray)(x = 35/382, y = -(152/191)# Explanation: #-x - 16y = 12, " Eqn (1)"# #12x + y = 8, " Eqn (2)"# #-12x - 192y + 12x + y = 144 + 8, " 12 * Eqn(1) + Eqn(2)"# #-191y = 152 " or " y = -(152/191)# Substituting value of y in Eqn (2), #12x - (152/191) = 8# #12x = (1528 + 152) / (8 * 191)# #x = 1680 / (12 * 8 * 191) = 35 / 382## Answer link Related questions What if the elimination method results in 0=0? How do you use the addition and subtraction method to solve a linear system? Can any system be solved using the addition and subtraction method? When is the addition and subtraction method easier to use? How do you solve #-x-6y=-18# and #x-6y=-6# using the addition and subtraction method? How do you solve #5x-3y=-14# and #x-3y=2# using elimination? Do you need to add or subtract the equations #5x+7y=-31# and #5x-9y=17# to solve the system? How do you solve the system of equations #3y-4x=-33# and #5x-3y=40.5#? What is the solution to the system #x+y=2# and #x-y=6#? What is the common point of #x+2y=6# and #x+y=2#? See all questions in Linear Systems with Addition or Subtraction Impact of this question 2132 views around the world You can reuse this answer Creative Commons License