How do you solve the quadratic equation by completing the square: $(2x-3)^2=8$ ?

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Answer 1 · 2015-07-22T00:04:27

I think you already completed the square (on the left)!!!

You can take the square root of both sides:
$2x-3=+-sqrt(8)$
so you get two solutions; rearranging:
$x_1=(3+sqrt(8))/2$
$x_2=(3-sqrt(8))/2$

How do you solve the quadratic equation by completing the square: (2x-3)^2=8(2x-3)^2=8?