How do you solve the quadratic equation by completing the square: $x^{2} + 24 = - 10 x$ $x^2 + 24 = - 10x$ ?

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How do you solve the quadratic equation by completing the square: $x^{2} + 24 = - 10 x$ $x^2 + 24 = - 10x$ ?

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Answer 1 · 2015-07-17T17:27:01

I found:
$x_{1} = - 4$ $x_1=-4$
$x_{2} = - 6$ $x_2=-6$

Explanation:

Try this:
$x^{2} + 10 x = - 24$ $x^2+10x=-24$
add and subtract $25$ $25$ :
$x^{2} + 10 x + 25 - 25 = - 24$ $x^2+10xcolor(red)(+25-25)=-24$
rearrange:
$x^{2} + 10 x + 25 = 25 - 24$ $x^2+10x+25=25-24$
${(x + 5)}^{2} = 1$ $(x+5)^2=1$
square root both sides:
$x^{2} + 5 = \pm \sqrt{1} = \pm 1$ $x^2+5=+-sqrt(1)=+-1$
so you get two solutions:
$x_{1} = - 5 + 1 = - 4$ $x_1=-5+1=-4$
$x_{2} = - 5 - 1 = - 6$ $x_2=-5-1=-6$

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How do you solve the quadratic equation by completing the square: $x^{2} + 24 = - 10 x$ $x^2 + 24 = - 10x$ ?

1 Answer

Explanation:

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Math

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How do you solve the quadratic equation by completing the square: x2+24=−10xx^2 + 24 = - 10x?

1 Answer

Explanation:

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How do you solve the quadratic equation by completing the square: $x^{2} + 24 = - 10 x$ $x^2 + 24 = - 10x$ ?