How do you solve the system $4 x + y - z = - 2$ $4x + y - z = -2$ , $x + 3 y - 4 z = 1$ $x + 3y - 4z = 1$ , $2 x - y + 3 z = 4$ $2x - y + 3z = 4$ ?

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Answer 1 · 2015-11-19T13:10:29

$x = - 1$ $x=-1$
$y = 6$ $y=6$
$z = 4$ $z=4$

The solution is given in the form of an image.
It is developed in Excel by me.
You have to supply the positive signs at the appropriate places.

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How do you solve the system 4x+y−z=−24x + y - z = -2, x+3y−4z=1x + 3y - 4z = 1, 2x−y+3z=42x - y + 3z = 4?