How do you solve the system $9x - 18y + 20z = -40$ $29x - 58y + 64= -128$ , $10x - 20y + 21z = -42$ ?

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Answer 1 · 2017-01-23T21:52:01

You can't find a unique (x,y.z) because the determinant of the matrix of coefficients is zero.

How do you solve the system 9x - 18y + 20z = -409x - 18y + 20z = -40 29x - 58y + 64= -12829x - 58y + 64= -128, 10x - 20y + 21z = -4210x - 20y + 21z = -42?