How do you solve the system of equations graphing #x+y=-2, 3x-y=10#?

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Answer 1 · 2016-12-17T17:09:33

#x = 2#
#y = -4#

#3x - y = 10#

#x + y = -2#

add equations:

#4x + 0 = -8#

#4x = -8#

divide both sides by 4:

#x = 8/4#

#x = 2#

substitute #x#:

#x + y = -2#

#2 + y = -2#

subtract 2 from both sides:

#y = (-2) - 2#

#y = -4#