How do you solve the system #x+y=4# and #x-y=2# by graphing?
1 Answer
Aug 3, 2017
See a solution process below:
Explanation:
First, draw the line for the first equation using two points:
graph{(x+y- 4)((x-4)^2+(y)^2-0.5)((x)^2+(y-4)^2-0.5)=0 [-40, 40, -20, 20]}
Next, draw the line for the second equation using two points:
graph{(x - y - 2)(x+y- 4)((x-4)^2+(y)^2-0.025)((x)^2+(y-4)^2-0.025)((x)^2+(y+2)^2-0.025)((x-2)^2+(y)^2-0.025)=0 [-10, 10, -5, 5]}
The lines are seen to intersect on the
The lines are seen to intersect on the
Therefore the solution is: