How do you solve the system #y=1/3x# and #y=1/3x-2# by graphing?

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Answer 1 · 2018-07-26T13:57:11

The solution is #S=O/#

Start by plotting

#y=1/3x#

graph{1/3x [-10, 10, -5, 5]}

This is a straight line passing through the origin.

Then on the same graph, plot

#y=1/3x-2#

graph{(y-1/3x)(y-1/3x+2)=0 [-10, 10, -5, 5]}

The graph are parallel, therefore, no solutions

We could have reached the same conclusions, as the gradients of the #2# lines are identical.

Gradient is #m=1/3#