How do you solve the system #y=1/3x# and #y=1/3x-2# by graphing?
1 Answer
Jul 26, 2018
The solution is
Explanation:
Start by plotting
graph{1/3x [-10, 10, -5, 5]}
This is a straight line passing through the origin.
Then on the same graph, plot
graph{(y-1/3x)(y-1/3x+2)=0 [-10, 10, -5, 5]}
The graph are parallel, therefore, no solutions
We could have reached the same conclusions, as the gradients of the
Gradient is