How do you solve the system #y-x=-1, x+y=8#? Algebra Systems of Equations and Inequalities Linear Systems with Addition or Subtraction 1 Answer ali ergin Nov 27, 2016 {x,y}={4.5,3.5} Explanation: #y-x=-1" "(1)# #x+y=8" "(2)# #"the sum of left sides of equations (1) ,(2)"# #y-cancel(x)+cancel(x)+y=2y# #"the sum of right sides of equations (1),(2)"# #-1+8=7# #2y=7# #y=7/2=3.5# #"now use (1) or (2)"# #3.5-x=-1# #x=3.5+1=4.5# Answer link Related questions What if the elimination method results in 0=0? How do you use the addition and subtraction method to solve a linear system? Can any system be solved using the addition and subtraction method? When is the addition and subtraction method easier to use? How do you solve #-x-6y=-18# and #x-6y=-6# using the addition and subtraction method? How do you solve #5x-3y=-14# and #x-3y=2# using elimination? Do you need to add or subtract the equations #5x+7y=-31# and #5x-9y=17# to solve the system? How do you solve the system of equations #3y-4x=-33# and #5x-3y=40.5#? What is the solution to the system #x+y=2# and #x-y=6#? What is the common point of #x+2y=6# and #x+y=2#? See all questions in Linear Systems with Addition or Subtraction Impact of this question 2103 views around the world You can reuse this answer Creative Commons License