How do you solve the triangle given A=124, a=1, b=2?

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How do you solve the triangle given A=124, a=1, b=2?

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Answer 1 · 2017-06-03T09:43:24

No solution!

Explanation:

Assuming you need to use the Law of Sines to determine the answer, you are being asked to find the angle $B$ $B$ , its opposite side $b$ $b$ , the angle $C$ $C$ and its opposite side $c$ $c$ . The picture and formula for the Law of Sines is

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Plugging in the givens, we have

$\frac{1}{sin (124)} = \frac{2}{sin (B)}$ $1/sin(124)=2/sin(B)$

Cross multiplying gets rid of the fractions.

$sin (B) = 2 \times sin (124)$ $sin(B)=2xxsin(124)$

Using radians, we get

$sin (B) \approx - 1.99$ $sin(B)~~-1.99$

And using degrees, we get

$sin (B) \approx 1.66$ $sin(B)~~1.66$

Unfortunately, neither of these answers is intelligible or coherent, because by definition, the $sin (B)$ $sin(B)$ must be between $- 1$ $-1$ and $1$ $1$ , that is:

$- 1 \leq sin (B) \leq 1$ $-1<=sin(B)<=1$

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How do you solve the triangle given A=124, a=1, b=2?

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