How do you solve the triangle given A=68, a=3, b=5?

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Answer 1 · 2018-02-25T10:23:31

With the given measurements, a triangle cannot be constructed.

There is a flaw in the given measurements.

Given $ˆ A = 68, a = 3, b = 5$ $hatA = 68, a = 3, b = 5$

To find $ˆ B, ˆ C, c$ $hat B, hatC, c$

Applying law of sines,

$\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{sin C}$ $a / sin A = b / sin B = c / sin C$

$sin B = \frac{b \cdot sin A}{a} = \frac{5 \cdot sin 68}{3} = 1.5453$ $sin B = (b * sin A) / a = (5 * sin 68) / 3 = 1.5453$

$sin θ$ $sin theta$ can not have a value more than 1.

Hence, with the given measurements, a triangle cannot be constructed.