Question

How do you solve the triangle given angle A=32degrees, C=44degrees, c=20?

Answer 1

`B=104^o`
`a=15.26`
`b=27.94`

Explanation:

First solve for angle B by subtracting your known angles (32 and 44) from 180. `180^o-32^o-44^o=104^o`

Then use law of sines to solve for a and b. `(sinA)/a=(sinB)/b=(sinC)/c`

`b/sin104=20/(sin44)` multiply both sides by sin104
`b=sin104(20/(sin44))=27.94`

`a/sin32=20/(sin44)`
`a=sin32(20/(sin44))=15.26`