How do you solve the triangle of $A = 110^{\circ}, a = 125, b = 200$ $A=110^circ, a=125, b=200$ ?

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Answer 1 · 2018-02-25T08:02:19

As sine theta cannot have a value above 1, triangle with the given measurements cannot exist.

$A = 110^{\circ}, a = 125, b = 200$ $A = 110^@, a = 125, b = 200$

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Applying Law of Sines,

$sin B = \frac{200 \cdot sin 110}{125} = 1.5035$ $sin B = (200 * sin 110) / 125 = 1.5035$

As sine theta cannot have a value above 1, triangle with the given measurements cannot exist.

How do you solve the triangle of A=110∘,a=125,b=200A=110^circ, a=125, b=200?