How do you solve using elimination of #3x=10-2y# and #5x-6y+30=0#?

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Answer 1 · 2018-06-13T15:22:32

#x=0#
#y=5#

#3x=10-2y# --- (1)
#5x-6y+30=0# --- (2)

From (1)
#3x=10-2y#
#x=1/3(10-2y)# --- (3)

Sub (3) into (2)
#5times1/3(10-2y)-6y+30=0#
#5/3(10-2y)-6y+30=0#
#50/3-10/3y-6y+30=0#
#140/3-28/3y=0#
#140-28y=0#
#140=28y#
#y=5# --- (4)

Sub (4) into (3)
#x=1/3(10-2y)#
#x=1/3(10-10)#
#x=0#

Answer 2 · 2018-06-13T15:24:05

#x=0,y=5#

Multiplying the first equation by #3# and adding to the second we get
#14x=0#
so
#x=0#
with this result we get
#y=5#