How do you solve using gaussian elimination or gauss-jordan elimination, $x - 2 y + z = - 14$ $x-2y+z=-14$ , $y - 2 z = 7$ $y-2z=7$ , $2 x + 3 y - z = - 1$ $2x+3y-z=-1$ ?

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How do you solve using gaussian elimination or gauss-jordan elimination, $x - 2 y + z = - 14$ $x-2y+z=-14$ , $y - 2 z = 7$ $y-2z=7$ , $2 x + 3 y - z = - 1$ $2x+3y-z=-1$ ?

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Answer 1 · 2017-12-20T16:08:43

$x = \frac{80}{7}$ $x=80/7$ , $y = - \frac{345}{7}$ $y=-345/7$ and $z = - 124$ $z=-124$

Explanation:

From $x - 2 y + z = - 14$ $x-2y+z=-14$ , $z = 2 y - x - 14$ $z=2y-x-14$

Hence $y - 2 \cdot (2 y - x - 14) = 7$ $y-2*(2y-x-14)=7$ or $2 x - 3 y = - 35$ $2x-3y=-35$ $(a)$ $(a)$ and,

$2 x + 3 y - (2 y - x - 14) = - 1$ $2x+3y-(2y-x-14)=-1$ or $3 x + y = - 15$ $3x+y=-15$ $(b)$ $(b)$

$3 x + y = - 15$ $3x+y=-15$ , $y = - 3 x - 15$ $y=-3x-15$

Consequently, $2 x - 3 \cdot (- 3 x - 15) = - 35$ $2x-3*(-3x-15)=-35$ and $- 7 x = - 80$ $-7x=-80$ , so $x = \frac{80}{7}$ $x=80/7$

Thus, $y = - 3 \cdot \frac{80}{7} - 15 = - \frac{345}{7}$ $y=-3*80/7-15=-345/7$ and $z = 2 \cdot (- \frac{345}{7}) - \frac{80}{7} - 14 = - 124$ $z=2*(-345/7)-80/7-14=-124$

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How do you solve using gaussian elimination or gauss-jordan elimination, $x - 2 y + z = - 14$ $x-2y+z=-14$ , $y - 2 z = 7$ $y-2z=7$ , $2 x + 3 y - z = - 1$ $2x+3y-z=-1$ ?

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How do you solve using gaussian elimination or gauss-jordan elimination, x−2y+z=−14x-2y+z=-14, y−2z=7y-2z=7, 2x+3y−z=−12x+3y-z=-1?

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How do you solve using gaussian elimination or gauss-jordan elimination, $x - 2 y + z = - 14$ $x-2y+z=-14$ , $y - 2 z = 7$ $y-2z=7$ , $2 x + 3 y - z = - 1$ $2x+3y-z=-1$ ?