How do you solve using gaussian elimination or gauss-jordan elimination, $X - 3 Y + 2 Z = - 5$ $X- 3Y + 2Z = -5$ , $4 X - 11 Y + 4 Z = - 7$ $4X - 11Y + 4Z = -7$ , $3 X - 8 Y + 2 Z = - 2$ $3X - 8Y + 2Z = -2$ ?

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Answer 1 · 2017-09-26T06:08:58

The solution is $((X),(Y),(Z))=((34+10Z),(13+4Z),(Z))$

Perform the gauss-jordan elimination on the augmented matrix

$((1,-3,2,|,-5),(4,-11,4,|,-7),(3,-8,2,|,-2))$

We perform the following operations on the rows

$R2larrR2-4R1$ and $R3larrR3-3R1$

$((1,-3,2,|,-5),(0,1,-4,|,13),(0,1,-4,|,13))$

$R3larrR3-R2$ and $R1larrR1+3R2$

$((1,0,-10,|,34),(0,1,-4,|,13),(0,0,0,|,0))$

The solution is

$((X),(Y),(Z))=((34+10Z),(13+4Z),(Z))$

How do you solve using gaussian elimination or gauss-jordan elimination, X- 3Y + 2Z = -5X−3Y+2Z=−5X- 3Y + 2Z = -5, 4X - 11Y + 4Z = -74X−11Y+4Z=−74X - 11Y + 4Z = -7, 3X - 8Y + 2Z = -23X−8Y+2Z=−23X - 8Y + 2Z = -2?