How do you solve using gaussian elimination or gauss-jordan elimination, $x - 3 y = 6$ $x-3y=6$ and $x + 6 y = 0$ $x+6y=0$ ?

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Answer 1 · 2018-03-12T10:59:08

$x = 4$ $x=4$ and $y = - \frac{2}{3}$ $y=-2/3$

From $x + 6 y = 0$ $x+6y=0$ , $x = - 6 y$ $x=-6y$ . Hence $x - 3 y = 6$ $x-3y=6$ became $- 9 y = 6$ $-9y=6$ . So,

$y = \frac{6}{- 9} = - \frac{2}{3}$ $y=6/(-9)=-2/3$ and $x = (- 6) \cdot (- \frac{2}{3}) = 4$ $x=(-6)*(-2/3)=4$

How do you solve using gaussian elimination or gauss-jordan elimination, x-3y=6x−3y=6x-3y=6 and x+6y=0x+6y=0x+6y=0?