How do you solve using the completing the square method $- 2 x^{2} - 7 x + 4$ $-2x^2 - 7x + 4$ ?

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How do you solve using the completing the square method $- 2 x^{2} - 7 x + 4$ $-2x^2 - 7x + 4$ ?

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Answer 1 · 2016-05-08T12:39:39

$- \frac{1}{2} and 4$ $-1/2 and 4$

Explanation:

Transform the equation for easier computation -->
$2 x^{2} + 7 x - 4 = 0$ $2x^2 + 7x - 4 = 0$ . Divide both sides by 2.
$x^{2} + \frac{7 x}{2} = 2$ $x^2 + (7x)/2 = 2$
$x^{2} + \frac{7 x}{2} + {(\frac{7}{4})}^{2} = 2 + \frac{49}{16}$ $x^2 + (7x)/2 + (7/4)^2 = 2 + 49/16$
${(x + \frac{7}{4})}^{2} = \frac{81}{16}$ $(x + 7/4)^2 = 81/16$
$(x + \frac{7}{4}) = \pm \frac{9}{4}$ $(x + 7/4) = +- 9/4$
$x = \frac{7}{4} \pm \frac{9}{4} = \frac{7 \pm 9}{4}$ $x = 7/4 +- 9/4 = (7 +- 9)/4$
x = 4 and $x = - \frac{2}{4} = - \frac{1}{2}$ $x = -2/4 = -1/2$

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How do you solve using the completing the square method $- 2 x^{2} - 7 x + 4$ $-2x^2 - 7x + 4$ ?

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