How do you solve using the completing the square method $3 x^{2} + 11 x - 4 = 0$ $3x^2 + 11x - 4 = 0$ ?

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How do you solve using the completing the square method $3 x^{2} + 11 x - 4 = 0$ $3x^2 + 11x - 4 = 0$ ?

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Answer 1 · 2017-08-04T05:06:45

-4; $\frac{1}{3}$ $1/3$

Explanation:

$3 x^{2} + 11 x = 4$ $3x^2 + 11x = 4$
Divide both sides by 3:
$x^{2} + \frac{11 x}{3} = \frac{4}{3}$ $x^2 + (11x)/3 = 4/3$
$x^{2} + \frac{11 x}{3} + \frac{121}{36} = \frac{4}{3} + \frac{121}{36}$ $x^2 + (11x)/3 + 121/36 = 4/3 + 121/36$
${(x + \frac{11}{6})}^{2} = \frac{169}{36}$ $(x + 11/6)^2 = 169/36$
$x + \frac{11}{6} = \pm \frac{13}{6}$ $x + 11/6 = +- 13/6$
$x = - \frac{11}{6} \pm \frac{13}{6}$ $x = - 11/6 +- 13/6$
$x 1 = - \frac{24}{6} = - 4$ $x1 = - 24/6 = - 4$
$x 2 = \frac{2}{6} = \frac{1}{3}$ $x2 = 2/6 = 1/3$

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How do you solve using the completing the square method $3 x^{2} + 11 x - 4 = 0$ $3x^2 + 11x - 4 = 0$ ?

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How do you solve using the completing the square method $3 x^{2} + 11 x - 4 = 0$ $3x^2 + 11x - 4 = 0$ ?