How do you solve using the completing the square method 3x^2 +18x +20 = 0?

1 Answer
P dilip_k
Apr 2, 2016

Dividing both sides of the Eq by 3 we have
x^2+6x+20/3=0
=>x^2+2xx3xxx+3^3-3^2+20/3=0
=>(x+3)^2-9+20/3=0
=>(x+3)^2-7/3=0
=>(x+3)^2-(sqrt(7/3))^2=0
=>(x+3+sqrt(7/3))(x+3-sqrt(7/3))=0
:.
(x=-3-sqrt(7/3))
and
(x=-3+sqrt(7/3))

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