How do you solve using the completing the square method 3x^2 + 2x + 5 = 03x2+2x+5=0?

1 Answer
Binayaka C.
Feb 14, 2017

Solution: x =-1/3 +sqrt (14)/3* i or x =-1/3 - sqrt (14)/3* i x=−13+√143⋅iorx=−13−√143⋅i

Explanation:

3x^2+2x+5 =0 or 3(x^2+2/3x) +5 =0 or 3(x^2+2/3x+(1/3)^2) -1/3+5 =0 3x2+2x+5=0or3(x2+23x)+5=0or3(x2+23x+(13)2)−13+5=0 or 3( x+1/3)^2 +14/3 =0 or ( x+1/3)^2 = -14/9 or x +1/3 = +-sqrt (-14/9)3(x+13)2+143=0or(x+13)2=−149orx+13=±√−149
or x = -1/3 +- sqrt (-14/9) :. x =-1/3 +sqrt (14)/3* i or x =-1/3 - sqrt (14)/3* i [i^2 = -1]
Solution: x =-1/3 +sqrt (14)/3* i or x =-1/3 - sqrt (14)/3* i [Ans]

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