How do you solve using the completing the square method 5v^2-21=10v5v2−21=10v?

1 Answer
maganbhai P.
Mar 10, 2018

v=1+sqrt(26/5)orv=1-sqrt(26/5)v=1+√265orv=1−√265

Explanation:

5v^2-21=10v=>5v^2-10v=21=>v^2-2v=21/color(red)55v2−21=10v⇒5v2−10v=21⇒v2−2v=215
:.v^2-2vcolor(red)(+1)=21/5color(red)(+1)=>(v-1)^2=26/5=(sqrt(26/5))^2
=>v-1=+-sqrt(26/5)=>v=1+-sqrt(26/5)
v=1+sqrt(26/5)orv=1-sqrt(26/5)

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