How do you solve using the completing the square method $5 x^{2} - 7 x + 2 = 0$ $5x^2 - 7x + 2 = 0$ ?

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How do you solve using the completing the square method $5 x^{2} - 7 x + 2 = 0$ $5x^2 - 7x + 2 = 0$ ?

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Answer 1 · 2016-04-11T03:15:27

$x = \frac{7 \pm 3}{10}$ $x = (7 +- 3)/10$

Explanation:

$5 x^{2} - 7 x = - 2$ $5x^2 - 7x = -2$ . Divide both sides by 5
$x^{2} - \frac{7 x}{5} = - \frac{2}{5}$ $x^2 - (7x)/5 = -2/5$
$x^{2} - \frac{7 x}{5} + \frac{49}{100} = - \frac{2}{5} + \frac{49}{100}$ $x^2 - (7x)/5 + 49/100 = - 2/5 + 49/100$
${(x - \frac{7}{10})}^{2} = \frac{9}{100}$ $(x - 7/10)^2 = 9/100$
$(x - \frac{7}{10}) = \pm \frac{3}{10}$ $(x - 7/10) = +- 3/10$
$x = \frac{7}{10} \pm \frac{3}{10} = \frac{7 \pm 3}{10}$ $x = 7/10 +- 3/10 = (7 +- 3)/10$

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How do you solve using the completing the square method $5 x^{2} - 7 x + 2 = 0$ $5x^2 - 7x + 2 = 0$ ?

1 Answer

Explanation:

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How do you solve using the completing the square method 5x2−7x+2=05x^2 - 7x + 2 = 0?

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How do you solve using the completing the square method $5 x^{2} - 7 x + 2 = 0$ $5x^2 - 7x + 2 = 0$ ?