How do you solve using the completing the square method 9x2−6x+1=0?

1 Answer
Lucy
Jun 9, 2018

x=−13

Explanation:

9x2−6x+1=0

First, divide every term by 9

x2−69x+19=0

Move your 19 to the RHS

x2−69x=−19

Simplify 69

x2−23x=−19

Now, your general form of a quadratic equation is ax2+bx+c=0
To complete the square, your equation looks something like this ax2+bx+(b2)2=−c

What this means is that you divide your coefficient of x by 2 and then square your entire number

x2−23x+(232)2=−19+(232)2

x2−23x+(13)2=−19+19

x2−23x+(13)2=0

(x+13)2=0

x=−13

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