How do you solve using the completing the square method $x^2 – 4x + 1 = 0$ ?

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Answer 1 · 2016-03-07T05:25:12

$x=2+sqrt3$ $or$ $2-sqrt3$

Given equation is $x^2-4x+1=0$

$x^2-4x=-1$ --------(1)

$third term =(1/2 xx$ coefficient of x $)^2$

$third term = (1/2xx -4)^2$

$third term = (-2)^2$

$third term =4$

Add 4 to both sides of equation 1

$x^2-4x+4=-1+4$

$(x-2)^2 = 3$

$(x-2)= +- sqrt3$

$x=2+-sqrt3$

$x=2+sqrt3$ $or$ $2-sqrt3$

How do you solve using the completing the square method x^2 – 4x + 1 = 0 x^2 – 4x + 1 = 0?