How do you solve using the completing the square method $x^{2} - 4 x = 12$ $x^2 - 4x =12$ ?

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How do you solve using the completing the square method $x^{2} - 4 x = 12$ $x^2 - 4x =12$ ?

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Answer 1 · 2018-04-10T21:13:55

$y = {(x - 2)}^{2} - 16$ $y=(x-2)^2-16$

Explanation:

First set the equation equal to 0

$x^{2} - 4 x - 12 = 0$ $x^2-4x-12=0$

Now complete the square

$[x^{2} - 4 x] - 12$ $[x^2-4x]-12$
$[{(x - 2)}^{2} - 4] - 12$ $[(x-2)^2-4]-12$
${(x - 2)}^{2} - 4 - 12$ $(x-2)^2-4-12$
${(x - 2)}^{2} - 16$ $(x-2)^2-16$

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How do you solve using the completing the square method $x^{2} - 4 x = 12$ $x^2 - 4x =12$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve using the completing the square method x2−4x=12x^2 - 4x =12 ?

1 Answer

Explanation:

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Impact of this question

How do you solve using the completing the square method $x^{2} - 4 x = 12$ $x^2 - 4x =12$ ?