How do you solve using the completing the square method $x^{2} + 4 x = 5$ $x^2+4x=5$ ?

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How do you solve using the completing the square method $x^{2} + 4 x = 5$ $x^2+4x=5$ ?

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Answer 1 · 2016-08-04T21:23:49

$x = 1$ $x=1$
$x = - 5$ $x=-5$

Explanation:

$x^{2} + 4 x = 5$ $x^2+4x=5$
or
$x^{2} + 4 x + 4 = 5 + 4$ $x^2+4x+4=5+4$
or
$x^{2} + 2 (x) (2) + 2^{2} = 9$ $x^2+2(x)(2)+2^2=9$
or
${(x + 2)}^{2} = 3^{2}$ $(x+2)^2=3^2$
or
$x + 2 = \pm 3$ $x+2=+-3$
or
$x = - 2 \pm 3$ $x=-2+-3$
or
$x = - 2 + 3$ $x=-2+3$
or
$x = 1$ $x=1$ ---------------Ans $1$ $1$
or
$x = - 2 - 3$ $x=-2-3$
or
$x = - 5$ $x=-5$ --------------Ans $2$ $2$

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How do you solve using the completing the square method $x^{2} + 4 x = 5$ $x^2+4x=5$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you solve using the completing the square method x2+4x=5x^2+4x=5?

1 Answer

Explanation:

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How do you solve using the completing the square method $x^{2} + 4 x = 5$ $x^2+4x=5$ ?