How do you solve using the completing the square method x2+6x+7=0?
1 Answer
Mar 31, 2017
Explanation:
To use the method of
completing the square
∙ add ( 1/2 coefficient of x-term)2 to both sides.
⇒x2+6x+32+7=0+32
⇒x2+6x+9=9−7
⇒(x+3)2=2 Take the
square root of both sides
√(x+3)2=±√2
⇒x+3=±√2
⇒x1=√2−3≈−1.6 to 1 dec. place
⇒x2=−√2−3≈−4.4 to 1 dec. place