How do you solve using the completing the square method $x^{2} + 7 x - 8 = 0$ $x^2+7x-8=0$ ?

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How do you solve using the completing the square method $x^{2} + 7 x - 8 = 0$ $x^2+7x-8=0$ ?

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Answer 1 · 2016-03-18T15:31:21

there are two roots and I have provided a video solution showing you how to complete the square by adding the square of 1/2 of the 'b' coefficient to both sides of the equation. This will allow you to come up with a trinomial that is a perfect square.

video solution here
so the solutions are -8 and 1

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How do you solve using the completing the square method $x^{2} + 7 x - 8 = 0$ $x^2+7x-8=0$ ?

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How do you solve using the completing the square method x2+7x−8=0x^2+7x-8=0?

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How do you solve using the completing the square method $x^{2} + 7 x - 8 = 0$ $x^2+7x-8=0$ ?