How do you solve using the completing the square method $x^{2} - 8 x + 12 = 0$ $x^2- 8x + 12 = 0$ ?

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How do you solve using the completing the square method $x^{2} - 8 x + 12 = 0$ $x^2- 8x + 12 = 0$ ?

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Answer 1 · 2017-11-01T10:34:11

$x = 2 or x = 6$ $x=2" or "x=6$

Explanation:

$place the constant term on the right side$ $"place the constant term on the right side"$

$\Rightarrow x^{2} - 8 x = - 12$ $rArrx^2-8x=-12$

$to use the method of completing the square$ $"to use the method of "color(blue)"completing the square"$

$∙ ensure the coefficient of the x^{2} term is 1$ $• " ensure the coefficient of the "x^2" term is 1"$

$x^{2} - 8 x = - 12 \leftarrow coefficient of 1$ $x^2-8x=-12larrcolor(blue)"coefficient of 1"$

$∙ add {(\frac{1}{2} coefficient of x-term)}^{2} to both sides$ $• " add "(1/2"coefficient of x-term")^2" to both sides"$

$x^{2} + 2 (- 4) x + 16 = - 12 + 16$ $x^2+2(-4)xcolor(red)(+16)=-12color(red)(+16)$

$\Rightarrow {(x - 4)}^{2} = 4$ $rArr(x-4)^2=4$

$take the square root of both sides$ $color(blue)"take the square root of both sides"$

$\Rightarrow x - 4 = \pm \sqrt{4} \leftarrow note plus or minus$ $rArrx-4=+-sqrt4larrcolor(blue)"note plus or minus"$

$\Rightarrow x = 4 \pm 2$ $rArrx=4+-2$

$\Rightarrow x = 4 + 2 = 6 or x = 4 - 2 = 2$ $rArrx=4+2=6" or "x=4-2=2$

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How do you solve using the completing the square method $x^{2} - 8 x + 12 = 0$ $x^2- 8x + 12 = 0$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve using the completing the square method x2−8x+12=0x^2- 8x + 12 = 0?

1 Answer

Explanation:

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Impact of this question

How do you solve using the completing the square method $x^{2} - 8 x + 12 = 0$ $x^2- 8x + 12 = 0$ ?