How do you solve using the completing the square method $x^{2} - 8 x = 9$ $x^2 - 8x = 9$ ?

Question

How do you solve using the completing the square method $x^{2} - 8 x = 9$ $x^2 - 8x = 9$ ?

1 Answer

Impact of this question

1227 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-27T04:26:17

It is

$x^{2} - 8 x = 9 \Rightarrow x^{2} - 8 x - 9 = 0 \Rightarrow {(x - 4)}^{2} - 25 = 0 \Rightarrow {(x - 4)}^{2} - 5^{2} = 0 \Rightarrow [x - 4 + 5] \cdot [x - 4 - 5] = 0 \Rightarrow (x + 1) \cdot (x - 9) = 0$ $x^2 - 8x = 9=>x^2-8x-9=0=> (x-4)^2-25=0=> (x-4)^2-5^2=0=> [x-4+5]*[x-4-5]=0=> (x+1)*(x-9)=0$

Hence the solutions are $x = - 1$ $x=-1$ and $x = 9$ $x=9$

Science

Math

Humanities

... and beyond

How do you solve using the completing the square method $x^{2} - 8 x = 9$ $x^2 - 8x = 9$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve using the completing the square method x2−8x=9x^2 - 8x = 9?

1 Answer

Related questions

Impact of this question

How do you solve using the completing the square method $x^{2} - 8 x = 9$ $x^2 - 8x = 9$ ?