How do you solve using the square root method $x^{2} + 5 = 86$ $x^2 + 5 = 86$ ?

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Answer 1 · 2016-04-14T04:54:25

$x = \pm 9$ $x = +-9$

To solve $x^{2} + 5 = 86$ $x^2+5=86$

We begin by isolating the term with $x$ $x$ by subtracting $5$ $5$ from both sides of the equation.

$x^2cancel(+5) cancel (-5)=86 -5$

We get

$x^2=81$

Now we square root both sides to eliminate the square of $x$

$sqrt(x^2) = sqrt81$

We get

$x = +-9$

How do you solve using the square root method x^2 + 5 = 86x2+5=86x^2 + 5 = 86?