How do you solve $x^{\frac{1}{2}} = 5$ $x^(1/2)=5$ ?

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Answer 1 · 2016-07-30T09:50:20

$x = 25$ $x=25$

$x^{\frac{1}{2}} = 5 ?$ $x^(1/2)=5 ?$

$x^{\frac{1}{2}} = \sqrt{x}$ $x^(1/2)=sqrt x$

${(\sqrt{x})}^{2} = {(5)}^{2}$ $(sqrt x)^2=(5)^2$

$x = 25$ $x=25$

How do you solve x^(1/2)=5x12=5x^(1/2)=5?