How do you solve $x^2 + 14x + 20 = 0$ by completing the square?

Question

3421 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-30T19:06:02

$x = -7 +- sqrt(29)$

$1(x^2 + 14x + n - n) = -20$

$n = (b/2)^2 = (14/2)^2 = 49$

$1(x^2 + 14x + 49 - 49) = -20$

$1(x^2 + 14x + 49) - 49 = -20$

$1(x + 7)^2 = 29$

$(x + 7) = +-sqrt(29)$

$x = +-sqrt(29) - 7$

Hopefully this helps!

How do you solve x^2 + 14x + 20 = 0x^2 + 14x + 20 = 0 by completing the square?