How do you solve $x^{2} + 2 x = 3$ $x^2 + 2x = 3$ by completing the square?

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How do you solve $x^{2} + 2 x = 3$ $x^2 + 2x = 3$ by completing the square?

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Answer 1 · 2016-05-26T21:23:52

$x = 1$ $x = 1$ or $x = - 3$ $x = -3$

Explanation:

In $x^{2} + 2 x$ $x^2 + 2x$ a third term is missing to be able to write the square of a binomial.
Find it by dividing the coefficient of $x$ $x$ by 2, square it and add to both sides.

$x^{2} + 2 x + 1 = 3 + 1$ $x^2 + 2x + color(red)1 = 3 + color(red)1$

${(x + 1)}^{2} = 4$ $(x + 1)^2 = 4$

$x + 1 = \pm \sqrt{4} = \pm 2$ $x + 1 = +-sqrt4 = +-2$

$x = + 2 - 1$ $x = +2 - 1$ or $x = - 2 - 1$ $x = -2-1$

$x = 1$ $x = 1$ or $x = - 3$ $x = -3$

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How do you solve $x^{2} + 2 x = 3$ $x^2 + 2x = 3$ by completing the square?

1 Answer

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How do you solve $x^{2} + 2 x = 3$ $x^2 + 2x = 3$ by completing the square?