How do you solve #x^(2/3)+15=24#?
1 Answer
Dec 9, 2016
Explanation:
Given:
#x^(2/3)+15 = 24#
Subtract
#x^(2/3) = 9#
Cube both sides to get:
#x^2 = 729#
Take the square root of both sides, allowing for both positive and negative square roots to get:
#x = +-27#
Assuming that we are dealing purely with Real numbers, both of these solutions are solutions of the original equation.