Question

How do you solve `x^2 3^x -8(3^x)= 0`?

Answer 1

`x=+-2sqrt2`

Explanation:

`"factor out "3^x`

`rArr3^x(x^2-8)=0`

`"equate each factor to zero and solve for x"`

`"note that "3^x!=0`

`rArrx^2-8=0rArrx^2=8rArrx=+-2sqrt2" is the solution"`