How do you solve $x^{2} - 3 x - 88 = 0$ $x^2 - 3x - 88 = 0$ by completing the square?

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How do you solve $x^{2} - 3 x - 88 = 0$ $x^2 - 3x - 88 = 0$ by completing the square?

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Answer 1 · 2016-05-06T13:24:37

x = -8 and x = 11

Explanation:

$x^{2} - 3 x = 88$ $x^2 - 3x = 88$
$x^{2} - (\frac{3}{2}) x + \frac{9}{4} = 88 + \frac{9}{4}$ $x^2 - (3/2)x + 9/4 = 88 + 9/4$
${(x - \frac{3}{2})}^{\circ} = \frac{361}{4}$ $(x - 3/2)^@ = 361/4$
Calculator gives -->
$(x - \frac{3}{2}) = \pm \frac{19}{2}$ $(x - 3/2) = +- 19/2$
$x = \frac{3}{2} \pm \frac{19}{2} = \frac{3 \pm 19}{2}$ $x = 3/2 +- 19/2 = (3 +- 19)/2$
x = 11 and x = -8

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How do you solve $x^{2} - 3 x - 88 = 0$ $x^2 - 3x - 88 = 0$ by completing the square?

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How do you solve x2−3x−88=0x^2 - 3x - 88 = 0 by completing the square?

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How do you solve $x^{2} - 3 x - 88 = 0$ $x^2 - 3x - 88 = 0$ by completing the square?